After Eq. (23), the sequence of inequalities has an extra 1/2 factor: According to working Eqs. (2) and (3), the inequality (23) is: (Formula presented.) Again, we know that the working formula to get the Fukui functionf(r)can be given by any of the three working equations that define the Fukui function as indicated by Eq. (6). Since: |f(2)(r)|<1, 0<f+(r)<1, 0<f-(r)<1, and 0<f¯(r)<1, we can replace|f(2)(r)|<1withf+(r), f-(r), orf¯(r)in the inequality (24): (Formula presented.) That is not correct because the 1/2 factor is already included in the definition of γ as indicated in the Eq. (3): (Formula presented.) As a consequence, γ=12I1+A1-I2-A2 is correct and not 12γ=12I1+A1-I2-A2 The correct writing is as follows: According to working Eqs. (2) and (3), the inequality (23) is: (Formula presented.) Again, we know that the working formula to get the Fukui functionf(r)can be given by any of the three working equations that define the Fukui function as indicated by Eq.(6). Since: |f(2)(r)|<1, 0<f+(r)<1, 0<f-(r)<1, and 0<f¯(r)<1, we can replace |f(2)(r)|<1withf+(r), f-(r), textitor f¯(r)in the inequality (24): (Formula presented.) This correction does not invalidate the demonstration that leads to Eq. (24) because the Eq. (23) is the end of the demonstration and the next lines correspond to simple replacements of the 12I1+A1-I2-A2, I1-A1-3, and I1-A1-2 with γ, η-3, and η-2, respectively. Finally, since η-1=S, the replacement finishes when, η-3, and η-2 are expressed as S3, and S2, respectively.